A rock is thrown downward from the top of a cliff If the rock hits the ground after 2.0 s, with a velocity of 12 m/s what is the height of the cliff?

Explanation:

v = u + a t

12 = 0 + 2a

a= 12/2

a=6 m/s2

v^2 - u ^2 = 2 as

12 ^2 - 0 ^2 = 2 * 6 * s

144 = 12 s

s = 144/12

s = 12 m

if they have a finite resultant

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hope this