A car accidentally rolls of cliff as it leaves the cliff it has a horizontal velocity of 15 m/s, it hits the ground 60m from the shore line calculate the height of the cliff

The height of the cliff is 78.4 m

Explanation:

Horizontal Launch Motion

When an object is thrown horizontally with a speed v from a height h, it describes a curved path exclusively ruled by gravity until it hits the ground.

The horizontal component of the velocity is always constant because no acceleration acts in that direction, thus:

The vertical component of the velocity changes in time because gravity makes the object fall at increasing speed given by:

Where g is the acceleration of gravity.

The maximum horizontal distance traveled by the object can be calculated as follows:

If the horizontal distance and the speed are known, we can solve the equation above for h:

The car leaves a cliff at a horizontal speed of v=15 m/s and hits the ground d=60 m from the shoreline. Thus the height of the cliff is:

Calculating:

h = 78.4 m

The height of the cliff is 78.4 m

gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.