a particle moves a distance of 190 ft along a straight line. As it moves, it is acted upon by a constant force of magnitude 15 lb in a direction opposite to that of the motion. What is the work done by the force

3868.1625 Nm

Explanation:

Given that:

Distance moved = 190 ft

Magnitude of force = 15 lb

Converting units :

1 lb = 4.45 Newton

1 ft = 0.305 meter

Hence,

Distance moved = (190 * 0.305) = 57.95 meter

Magnitude of force = (15 * 4.45) = 66.75 Newton

Workdone = Force * distance

Workdone = 66.75 N * 57.95 m

Workdone = 3868.1625 Nm

the answer is a. the yacht traveled from the dock north to the 200-meter marker in the bay in less than 5 minutes, giving the passengers several more hours to fish.

im doing peak rn so sry if its wrong

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west