g A cylinder of length 2.75 m, radius 0.420 m, and mass 14.7 kg is rotated at an angular speed of 3.70 rad/s around an axis parallel to the length of the cylinder and through its center. Find the magnitude of the cylinder's angular momentum.

4.792 kgm²/s

Explanation:

Given that

Length of the cylinder, l = 2.75 m

Radius of the cylinder, r = 0.42 m

Mass of the cylinder, m = 14.7 kg

Angular speed of rotation, v = 3.7 rad/s

The magnitude of a cylinders angular momentum is given by the formula

L = I * v, where

I = moment of inertia about the axis given by mr²/2

I = (14.7 * 0.42²) / 2

I = 2.59 / 2

I = 1.295 kgm

L = I * v

L = 1.295 * 3.7

L = 4.792 kgm²/s

Therefore, the angular momentum of the cylinder is 4.792 kgm²/s

given data:

determine the horse power (h.p) = ?

force applied to move the box(f) = 10 pounds,

box lifted from a distance         (d) = 3 feet

time taken to lift                         (t) = 10 sec,

the horse power is defined as amount of work required to move a load. the horse power is equal to 550 foot-pound per second

                  1 h.p   = 550 foot-pound/second

it can also be defined as the the load that need to be move a body for certain distance in a certain amount of time.

mathematically,

                      h.p = (force × distance)/ time

                            = (10 × 3)/ 10

                            = 30/10

                            = 3 foot -pound/sec

hence, the horse power is needed to move the box is 3 foot-pound/second

important note: 1 h.p = 550 foot-pound/second = 746 watts

0.863333

86%

hope this