A 1370-kg small aircraft accelerates along the runway from 7.4 m/s to 37.8 m/s in 5.20 seconds. Determine the net force acting upon the plane. (Assume that its engine/propeller makes no contributes to its forward motion)

8009 N

Explanation:

Given that a 1370-kg small aircraft accelerates along the runway from 7.4 m/s to 37.8 m/s in 5.20 seconds. Determine the net force acting upon the plane. (Assume that its engine/propeller makes no contributes to its forward motion)

According to the definition of acceleration, acceleration is the change in velocity per time taken.

Acceleration a = ( 37.8 - 7.4 )/ 5.2

Acceleration a = 30.4 / 5.2

Acceleration a = 5.846 m/s^2

Force = mass × acceleration

Force = 1370 × 5.846

Force = 8,009 N

Therefore, the net force acting upon the plane is 8009 N. (Assume that its engine/propeller makes no contributes to its forward motion)

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2