Two particles, an electron and a proton, move in a circular path in a uniform magnetic field of intensity B=1.23 T. Find the ratio between the time period of the proton Tp to the electron Te (i. e., find 'p)

The ratio of the time period of the proton to the electron is 1835.16.

Explanation:

Given that,

Two particles, an electron and a proton, move in a circular path in a uniform magnetic field of intensity B=1.23 T

We need to find the ratio between the time period of the proton Tp to the electron Te.

The time period in magnetic field is given by :

For proton, time period is :

For an electron, the time period is :

From equation (1) and (2) :

So, the ratio of the time period of the proton to the electron is 1835.16.

i agree kid

explanation:

a

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day