Sugar crystals enter a dryer at the rate of 1000 kg h-1 and at 20% w. b. moisture content. They leave the dryer at 3% w. b. moisture content. If the drying process requires 3000 kJ kg-1 of water removed, estimate the amount of heat required per hour and the rate of dry crystals out of the dryer.

The dryer evaporate 200 - 24.74 kg of water per hour

To remove 1kg of water it need 3000 K J

So to remove, 175.26 Kg

it need 5.257x KJ of heat per hour.

Explanation:

In one hour, the amount of sugar entering = 1000 kg

w.b moisture content is defined as,

weight of water / weight of water + weight of dry

/ + x 100

+ = 1000 kg when entering

it has 20% moisture content when entering

= 0.2 x 1000 = 200 kg

when leaving it has 3% moisture content then weight of dry material

= 1000 - 200 = 800 Kg

= 0.03

= 0.03

= 0.03 x + 0.03 x 800

= 24.74 kg

When leaving the dryer, the crystals has total weight of the water = 24.74 kg per hour.

The dryer evaporate 200 - 24.74 kg of water per hour

To remove 1kg of water it need 3000 K J

So to remove, 175.26 Kg

it need 5.257x KJ of heat per hour.

i had this question and the answer was 3.15 miles.

martina travels from school to her mom's office. from there, she walks to school. after school, she walks to the library and then to a friends house before finally ending back at home. find martina's total distance traveled.

a) 0 miles  

b) 0.4 miles  

c) 1 mile  

d) 3.15 miles