Q. a ball of relative density 0.8 falls into water from a height of 2m. find the depth to which the ball will sink ?

First, we need to find the speed of the ball using the equation of motion: with g = 9.8 and h=2

= 6.32 m/s

Now we need to calculate the force which the water used to try to stop the ball using the Buoyancy force d*v*g
d*v*g = ma
a =

Let the density of the ball be d'
m=d'V
a=
a=
a= * g

Relative density d/d' = 0.8
a =
a=

a = 12.25 /s
 deceleration a'=a-g = 2.45 /s

The final speed of the ball is v'=0
-v'^2 = v^2 + 2a's
40 = 0+2*2.5s
s=8m

The depth to which the ball will sink is 8m

Hope this Helps! :D

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