Calculate the total energy transferred when 200 g of ice cubes at 0°C are changed to steam at 100°C. Specific heat capacity of water = 4200 J/kg °C
Specific latent heat of fusion = 340 kJ/kg
Specific latent heat of vaporisation = 2260 kJ/kg

Explanation:

m = Mass of ice = 200 g

= Temperature change of water =

c = Specific heat capacity of water = 4200 J/kg °C

= Specific latent heat of fusion = 340 kJ/kg

= Specific latent heat of vaporisation = 2260 kJ/kg

Heat required to convert ice to water =

Heat required to raise the temperature of water to boiling point =

Heat required to convert water to steam =

Total heat required

Heat required to convert the given amount of ice to steam at the required temperature is .

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s