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Physics, 03.01.2021 23:40 KillerSteamcar

A merry-go-round initially at rest at an amusement park begins to rotate at time t=0 . The angle through which it rotates is described by θ(t)=(π/k)*(t+ke^(−t/k)) , where k is a positive constant, t is in seconds, and θ is in radians. The angular velocity of the merry-go-round at t=T is Zero

(5/2)kπ

(π/k)*(1−e^(−Tk))

π


A merry-go-round initially at rest at an amusement park begins to rotate at time t=0 . The angle th

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A merry-go-round initially at rest at an amusement park begins to rotate at time t=0 . The angle thr...
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