A basketball is rolling rightward onto the court with a speed of 4.0 m/s and slows down with a consta leftward acceleration of magnitude 0.50 m/s^2 over 14 m. What is the velocity of the basketball after rolling for 14 m?
a. 2.0 m/s
b. 5.5 m/s
c. 7.5 m/s
d. 1.4 m/s

d. 1.4 m/s

Explanation:

Given;

initial velocity of the `basketball, u = 4.0 m/s

acceleration of the basketball, a = -0.5 m/s² (leftward)

distance the basketball traveled, d = 14 m

the final velocity of the basketball, v = ?

(this final velocity should be less than the initial velocity since the ball is slowing down at a constant rate)

Apply the following the kinematic equation;

v² = u² + 2ad

v² = 4² + 2(-0.5)14

v² = 16 - 14

v² = 2

v = √2

v = 1.41 m/s

Therefore, the final velocity of the basketball is 1.4 m/s.

a

explanation:

all resources in america come from jesus

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz