A student lifts a 1.4-kg box of magazines vertically from rest with an upward force of 52.7 N. The distance of the lift is 1.6 meters. Find the total work done on the box

-64.41

The total work done on the box is 21.952 Joules

The workdone on the box is equal to the potential energy possessed by the body. Mathematically;

Given the following parameters

m = 1.4kg

g  = 9.8m/s²

h = 1.6m

Substitute the given parameters into the formula:

Hence the total work done on the box is 21.952 Joules

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The work done on the box is 21.952 Joules

Explanation:

The given parameters are;

The mass of the box of magazines, m = 1.4 kg

The upward force with which the student lifts the magazine = 52.7 N

The distance (height) of the lift, h = 1.6 meters

The work done on the box = The potential energy gained by the box of magazine, P. E.

Potential energy gained by elevation, P. E. = Mass, m × The acceleration due to gravity, g × Height, h

Where;

The acceleration due to gravity, g = 9.8 m/s²

∴ P. E. = m × g × h = 1.4 kg × 9.8 m/s^2 × 1.6 m = 21.952 Joules

The work done on the box = The potential energy gained by the box of magazine, P. E. = 21.952 Joules

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