Caris parked on road slopes upward at angle θ. The magnitude the force of the road on the is mg cosθ. Is the magnitude of the stalie friction force on the less equal to or greater than μ2mgcosθ? Explain.

fr = μ m g cos θ

the correct answer is less than fr = μ 2m g cos θ

Explanation:

Let's propose the solution of the problem to be able to answer the question, let's fix a reference system with one axis parallel to the plane (x-axis) and the other perpendicular, let's write Newton's second law

Y Axis  

     N - W cos θ = 0

     N = mg cos θ

X axis.

     fr - w sin θ = 0

     fr = mg sin θ

the friction force is described by the expression

     fr = μ N

      fr = μ m g cos θ

When we analyze this expression we see that the friction force is equal to (μ_k m g cos θ)

If everything is well written in your problem, the correct answer is less, even though I think you have an error when writing the number

be subject to a force andchange its motion