A boy rubs two balloons against his sweater. One balloon acquires a charge of 3.0 E -6 C. The other balloon acquires a charge of 2.5 E -7 C. If the balloons are positioned 1 cm apart, what is the electrical force between them?

67.5 N

Explanation:

From the question given above, the following data were obtained:

Charge 1 (q₁) = 3.0×10¯⁶ C

Charge 2 (q₂) = 2.5×10¯⁷ C

Distance apart (r) = 1 cm

Force (F) =?

Next, we shall convert 1 cm to m. This can be obtained as follow:

100 cm = 1 m

Therefore,

1 cm = 1 cm × 1 m / 100 cm

1 cm = 0.01 m

Thus, 1 cm is equivalent 0.01 m.

Finally, we shall determine the electrical force between the two points charges as follow:

Charge 1 (q₁) = 3.0×10¯⁶ C

Charge 2 (q₂) = 2.5×10¯⁷ C

Distance apart (r) = 0.01 m

Electrical constant (K) = 9×10⁹ Nm²C¯²

Force (F) =?

F = Kq₁q₂ / r²

F = 9×10⁹ × 3.0×10¯⁶ × 2.5×10¯⁷ / (0.01)²

F = 0.00675 / 0.0001

F = 67.5 N

Therefore, the electrical force between the two points charges is 67.5 N

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