An engineer is designing a runway for an airport. Of the planes that will use this airport, the lowest acceleration rate is likely to be 4 m/s^2. The
takeoff speed of this plane will be 80 m/s. Assuming this is the minimum
acceleration, what is the minimum allowed length for the runway? (vf^2 =
vi^2 + 2a(df-di)) *

704m

Explanation:

Given, initial velocity, u=0m/s and final velocity v=65m/s

Acceleration a=3m/s 2

If d be the allowed length for the runway.

Using formula v*2 −u*2 =2aS

(65)*2−0*2 =2(3)d

⟹ d=65*2 /6=704.16∼704m

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the following is queen elizabeth’s purposes:

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