A Go Kart (m = 35 kg) has a top speed of 12 m/s . A student traveling at top speed locks the brake to avoid hitting a bus after school, skidding 7.2 meters before stopping. How much force did the Go Kart have when the student locked the brake?

350 N

Explanation:

From the question given above, the following data were obtained:

Mass (m) of Go Kart = 35 kg

Initial velocity (u) = 12 m/s

Distance (s) = 7.2 m

Force (F) =?

Next, we shall determine the acceleration of the Go Kart. This can be obtained as follow:

Initial velocity (u) = 12 m/s

Distance (s) = 7.2 m

Final velocity (v) = 0 m/s

Acceleration (a) =.?

v² = u² + 2as

0² = 12² + (2 × a × 7.2)

0 = 144 + 14.4a

Collect like terms

0 – 144 = 14.4a

– 144 = 14.4a

Divide both side by 14.4

a = – 144 / 14.4

a = – 10 m/s²

The negative sign indicate that the Go Kart is decelerating when the brake was applied.

Finally, we shall determine the force the Go Kart have when the student locked the brake. This can be obtained as follow:

Mass (m) of Go Kart = 35 kg

Acceleration (a) = 10 m/s

Force (F) =?

F = ma

F = 35 × 10

F = 350 N

Thus, the Go Kart has a force of 350 N when the student locked the brake.

f=ma newton's second law 7x8=56n

490 n

f=125n a=2.5m/s2