You are at the Grand Canyon, standing at the edge of a ledge 1,857 m high. You have a mass of 61 kg. You decide to take a selfie to share with your science teacher when you get home which causes you to wonder... a. How much gravitational potential energy do you have standing at the edge of this cliff?

b. If you were to trip and fall mid-selfie, your stored potential energy would be converted to kinetic energy, as you are in motion. Assume that all of the GPE you calculated in part A would be converted to kinetic energy when you fall. If so, how fast would you be falling?

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

Attach the free body diagram and i will you answer the question.! : d