The amount of work (W) done on an object is equal to the force (F) needed to lift the object (the object’s weight) multiplied by the distance (d) the object is lifted: W = F ✕ d.
Use the weight of the ball that you calculated in activity B to determine how much work
would be required to lift the ball 2 meters above the zero position:

Work done during lifting up body is 0

Explanation:

From the question it is given that

Distance traveled by body during lifting is 2 m

since work done by body is given by

work done W = F x s x cosθ

Where F= mg = weight of body

s= distance traveled = 2m

θ = angle between force and distance vector

here θ = 90° as body is lifting up

on substituting the respected values we get

⇒ W = mg x 2 x cos90° = 0   {∵ cos90°= 0 }

Thus, work done during lifting up body is 0

that would be b i just took the test : )

b

step-by-step explanation: a third of 24 is 8, 8 times 3 is 24 so 8 - 2 would be 6