Mark, a 73 kg physics student, rides a rollercoaster. At the bottom of a steep dive he experienced a net force of 1600 N. What was his acceleration at that point? Show your work.

21.9m/s²

Explanation:

Given parameters:

Mass of the physics student  = 73kg

Net force  = 1600N

Unknown:

The acceleration at this point  = ?

Solution:

To solve this problem, we apply a knowledge of Newton's second law of motion which is mathematically expressed as;

        F  = m a

F is the friend

m is the mass

a is the acceleration

          1600  = 73 x a

              a  = 21.9m/s²

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