A large semi-truck is moving a house from one lot to another. The amount of force required to move the house 15.A horizontally a distance of 72 meters is 3.500 pewtens How much work will be done ce the house?

252J

Explanation:

Given parameters:

Distance  = 72m

Force  = 3.5N

Unknown:

Work done on the house  = ?

Solution:

Work done is the force applied to move a body through a particular distance.

    Work done  = Force x distance

Now insert the parameters and solve;

   Work done  = 3.5 x 72  = 252J

fgravity=10x10=100n case 1

fgravity=30x20=600n case 2

6 times more

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft