where V is the voltage in volts, I is the current in amperes, and R is the resistance in ohms. Assume that, as the battery wears out, the voltage decreases at 0.03 volts per second and, as the resistor heats up, the resistance is increasing at 0.02 ohms per second. When the resistance is 100 ohms and the current is 0.02 amperes, at what rate is the current changing

Explanation:

From the question we are told that

Voltage change

Resistance change

Resistance

Current

Generally the equation for ohms law is mathematically represented as

Therefore

Resolving the Rate of current changing as subject of formula

Therefore

Therefore the current decreases at a rate

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