approaching a dangerous intersection the driver slows her car from 40 meters per second to 15 meters per second in 5 seconds what is the acceleration

- 5 m/s^2

Explanation:

Givens

vi = 40 m/s

vf = 15 m/s

t = 5 seconds

Formula

a = (vf - vi)/t

a = (15 - 40)/5

a = -25/5

a = - 5 m/s^2

Don't be bothered by the minus sign. It just means she is slowing down.

for this one it would be d bump/forearm pass

the tires are rotating at 0.434 rpmlinear speed=45 m/sdiameter=0.550 mradius=0.275 mnow v= rωω= v/rω=45/0.275ω=163.6 rad/sω=163.6 rad/s (1rev/2π rad) (60s/1m)ω=1563 rpm