In the reaction _S+302 +2SO3, what coefficient should be placed in front of the S to balance the reaction? A. 1
B. 2
C. 3
D.5

B. 2

Explanation:

The reaction expression is given as:

                _S  + 3O₂   →  2SO₃

Now let us balanced the expression;

  On the product side we have 2 moles of S

   On the reactant side we should have 2moles of S

So, we put the coefficient 2 to balance the expression;

   We have 6 moles oxygen on both sides

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