A 3 kg block is attached to a spring of spring constant k = 250 N/m. The block is pulled to a maximum distance (amplitude) of 8 cm What is the value of the spring force when the block is at 8 cm?

20 N

Explanation:

From the question given above, the following data were obtained:

Mass (m) of block = 3 Kg

Spring constant (K) = 250 N/m

Extention (e) = 8 cm

Force (F) =?

Next, we shall convert 8 cm to m. This can be obtained as follow:

100 cm = 1 m

Therefore,

8 cm = 8 cm × 1 m / 100 cm

8 cm = 0.08 m

Thus, 8 cm is equivalent to 0.08 m.

Finally, we shall determine the force when the block is at 8 cm (i.e 0.08 m). This can be obtained as follow:

Spring constant (K) = 250 N/m

Extention (e) = 0.08 m

Force (F) =?

F = Ke

F = 250 × 0.08

F = 20 N

Thus, the force is 20 N.

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