Identify the state of matter. A)The molecules are a great distance apart, moving
very rapidly, with negligible interaction. The
substance occupies all the space available.
B)The molecules are only able to vibrate rapidly about
fixed positions. The substance does not need a
container to maintain its shape.
C)The molecules move about amongst each other,
with attractive forces between them. The substance
does not necessarily fill its container

Gases

Solids

Liquids

Explanation:

A)The molecules are a great distance apart, moving  very rapidly, with negligible interaction. The  substance occupies all the space available.

Gases

The state of matter described above is for gases. The distances between gases are far apart and they have very weak intermolecular attraction. They have no fixed volume as they occupy any volume of space they are introduced into.

B)The molecules are only able to vibrate rapidly about  fixed positions. The substance does not need a  container to maintain its shape.

Solids

Solids have fixed shape and volume. They are held together in their fixed lattice and are only able to rapidly vibrate about their fixed positions.

C)The molecules move about amongst each other,  with attractive forces between them. The substance  does not necessarily fill its container.

Liquids

The state of matter described here are the liquids. Liquids flow amongst each other. The attractive force between them is greater than that of gases but lesser than those of solids.

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz