The planet Venus has a mass of 4.87 x 10^24 kg and a radius of 6.05 x 10^6 km. What is the magnitude of the gravitational force that an 81-kg person would experience while
standing on the surface of Venus?
(A) 179 N
(B) 719 N
(C) 259 N
(D) 7.19 x 10^8N
(E) 4.19 x 10^9N

The gravitational force that an 81-kg person would experience while standing on the surface of Venus is approximately;

(A) 719 N

Explanation:

The question relates to gravity calculation for which we use the Newton's gravitational law which is presented as follows;

Where;

G = The universal gravitational constant = 6.67408 × 10⁻¹¹ m³kg⁻¹s⁻²

F = The gravitational force between the two masses, "M" and "m"

r = The distance between the centers of the two masses

M = The mass of one body interacting in the gravitational force

m = The mass of the other body interacting in the gravitational force

The given parameters are;

The mass of Venus, M = 4.87 × 10²⁴ kg

The radius of the planet Venus, r (is corrected) = 6.05 × 10³ km  = 6.05 × 10⁶ km

The mass of the person standing on the surface of Venus, m = 81-kg

Therefore, by plugging in the values, we get;

From Newton's third law of motion, the gravitational force that the 81-kg person experiences while standing on the surface of Venus = F ≈ 719 N.

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees.