A string has a mass of 0.8Kg. The length of the string is 2m. The tension in the string is 5N. The string is stretched and fixed at both ends such that when struck it forms the second harmonic. Calculate the frequency of the wave which results on the string.

1.25Hz

Explanation:

For waves on a string, the second harmonic is obtained from;

2fo = 1/l √T/M

Where;

l = length of the string

M= mass in kilograms

T = tension in the string

2fo = 1/2√5/0.8

2f0 = 1.25Hz

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since we're talking about water, the freezing point of water will be 32 degrees fahrenheit or below.

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