An airplane maintains a speed of 669 km/h relative to the air it is flying through as it makes a trip to a city 675 km away to the north. (a) What time interval is required for the trip if the plane flies through a headwind blowing at 33.0 km/h toward the south

1.06 h

Explanation:

Assuming that the airplane is traveling through the air, moving at a sites relative to the ground. The airplane is expected to make a displacement of 675 km due North.

Let north y be positive, and west x also be positive, then

With the wind blowing at 33 km/h due South. We then say,

The northern component of the velocity of the airplane you the ground is

669 km/h - 33 km/h = 636 km/h

Then, the time interval taken by the airplane to travel 675 km is

675 / 636 = 1.06 h

Therefore, we can conclude that the answer is 1.06 h

air exerts forces on falling objects near earth’s surface.

explanation:

the term 'free falls' refer to object that are falling towards the earth, in a situation in which gravity is the only force acting on the object.

for an object in free fall, the acceleration is constant (g, the gravitational acceleration), and so the velocity of the object constantly increases.

for objects near earth's surface, there is always another force acting on the object: the resistance due to the air. this force is opposed to the direction of fall of the object, and it is proportional to the velocity of the object, so as the object falls down, this force increases up to a point when it balances the force of gravity, and the object continues its motion at constant velocity (called terminal velocity). since in this case gravity is not the only force acting on the object, we are not in a situation of free fall.