g A box of mass 10 kg attached to a spring is pulled to a maximum of 44 cm. The box is released. What is the speed when the box reaches a point 10 cm from the equilibrium position

The speed when the box reaches a point 10 cm from the equilibrium position is 2.02 m/s.

Explanation:

Mass attached to the spring, m = 10 kg

maximum displacement of the spring, A = 0.44 m

The spring constant is calculated from Hook's law;

F = kx

mg = kx

k = (mg) / x

k = (10 x 9.8) / 0.44

k = 222.73 N/m

The angular speed of the spring is calculated as;

The speed when the box reaches a point 10 cm from the equilibrium position is calculated as;

Therefore, the speed when the box reaches a point 10 cm from the equilibrium position is 2.02 m/s.

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