If the potential difference across the filament is 120 V, what is the strength of the electric field inside the filament

200 N/C

Explanation:

Given that the length of a 60 W, 240 & Omega light bulb filament is 60 cm. If the potential difference across the filament is 120 V, what is the strength of the electric field inside the filament?

The parameters needed from the question are:

Potential difference V = 120v

Distance ( Length) = 60 cm

Convert cm to m by dividing it by 100

Distance = 60/100

Distance = 0.6 m

The formula for electric field strength E is:

E = V/d

Where

V = potential difference

d = distance

Substitute those parameters in the formula

E = 120 / 0.6

E = 1200 / 6

E = 200 N/C

Therefore, the strength of the electric field inside the filament is 200N/C

the answer is b ) square root of 5