A rifle is aimed horizontally at the center of a large target 60 m away. The initial speed of the bullet is 240 m/s. What is the distance from the center of the target to the point where the bullet strikes the target

The distance from the center of the target to the point where the bullet strikes the target is 0.31 m.

Explanation:

Given;

the position of center of the target, x₀ = 60 m

initial velocity of the bullet, u = 240 m/s

The time the bullet strikes the center of the large target is calculated as;

The distance from the center of the target to the point where the bullet strikes the target is calculated as;

x = vt + ¹/₂gt²

where;

v is the final velocity of the bullet when it strikes the target = 0

x = 0 + ¹/₂(9.8)(0.25²)

x = 0.31 m

Therefore, the distance from the center of the target to the point where the bullet strikes the target is 0.31 m.

total distance travelled = 60 miles

total time taken =1.5 hours

average speed = total distance / total time

60 / 1.5

= 40

therefore, average speed = 40 m/h

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the simple machine has three main features. they are:

fulcrum is the center point or pivot point of the machine. effort is input force/ applied force. load is external force/ output.

the keisha 's machine labels are

x : load

y: fulcrum

z: lever