A 30 kg girl and a 40 kg boy stand on rollerskates, face one another, and push off each other. If the boy accelerates backward with an acceleration of 6 m/s 2 , what will be the acceleration of the girl?

the acceleration of the girl is 8 m/s² in opposite direction.

Explanation:

Given;

mass of the girl, m₁ = 30kg

mass of the boy, m₂ = 40 kg

acceleration of the boy, a₂ = 6 m/s²

let acceleration of the girl = a₁

Apply Newton's third law of motion;

the force exerted by the girl is equal  in magnitude  to the force exerted by the boy but in opposite direction.

F₁ = -F₂

m₁a₁ = -m₂a₂

30a₁ = -(40 x 6)

30a₁ = -240

a₁ = -240 / 30

a₁ = -8 m/s² (the negative sign shows that the acceleration is in opposite direction)

Thus, the acceleration of the girl is 8 m/s² in opposite direction.

nah.   i'm just sleepy.

i just did an experiment like this in my science class. also the answer is yes, it will get separated because they are two opposites meaning if they are opposite they can not attract.

hope this .!