A 3400 kg jet is flying at a constant speed of 170 m/s as it makes a vertical loop. At the top of the loop the pilot feels three times his normal weight. What is the radius of the loop

736.49 meters

Explanation:

Step one:

Given data

mass m= 3400kg

speed= 170 m/s

At the top of the loop the pilot feels three times his normal weight

hence we multiply mass by 3 in our solution

Centrepetal force = mv^2/r-mg=3mg

Thereofore, (his true weight) + (the weight he feels) = mg + 3mg

so

mv^2/r=4mg

Step two:

centripetal force = mv^2/r=4mg

mv^2=4mgr

v^2=4gr

substitue

centripetal force

170^2 = 4*3400*9.81

so

170^2 = 4*9.81*r  

28900 = 39.24*r  

28900 =39.24*r  

divide both sides by 39.24

r=28900 /39.24

r=736.49 meters

54 degrees incident angle = reflected angle

angle is from normal turned to line of ray

the answer is the index of refraction of the second medium is higher. i just took the test.