Rafael is driving his car at 26 m/s. What is the shortest distance in which he can brake and stop if the coefficient of static friction between the tires and the road is 0.4

86.14 meters.

Explanation:

Step one:

Given data

velocity of car = 26 m/s

the coefficient of static friction between the tires and the road

µ = 0.4 (kinetic)

Let us take g = 9.81 m/s^2

Required

The distance x = distance in m

We know that

W = F*x  (Work is force times distance)

Step two:

Conservation of energy gives  

KE = W

Substituting gives  

Solving for distance (x) gives  

Simplifying

Substitute:  

Therefore, the minimum braking distance is 86.14 meters.

the small 0.38-kg slider is known to move from position a to position b along the vertical-plane slot. determine (a) the work done on the body by its weight and (b) the work done on the body by the spring. the distance r = 0.70 m, the spring modulus k = 154 n/m, and the unstretched length of the spring is 0.53 m

explanation:

-reverse card

total distance/total time

(85 + 82)/(5+3)

167/8

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