The bottom of a box has a surface area of 58.8 cm 2 . The mass of the box is 12.0 kg. Acceleration due to gravity at sea level is 9.80 m/s 2 . What is the pressure exerted by the box where it rests

P = 20 kPa

Explanation:

Given that,

The surface area of the bottom of the box, A = 58.8 cm² = 0.00588 m²

The mass of the box, m = 12 kg

The acceleration due to gravity, g = 9.8 m/s²

We need to find the pressure exerted by the box where it rests. Oressure is equal to the force acting per unit area. So,

Pressure = Force/Area

So, the required pressure is 20 kPa.

two charges are fixed in place on the x-axis as shown. the charge at x = 0 is negative and has magnitude q = 2 μcoulombs (1 μcoulomb = 10-6 coulombs). the charge at x = d, (d = +12 cm), is positive and has magnitude q = 4 μcoulombs. find a point x = xo along the x-axis at which the electric field is zero.

i think it's 35 meters