A spring with a spring constant of 500 N/m is stretched 1 meter in length. How much elastic potential energy does the spring have stored in it?

E =250 J

Explanation:

Given that,

The spring constant of the spring, k = 500 N/

It is stretched to a distance of 1 m

We need to find how much elastic potential energy does the spring have stored in it.

The energy stored in the spring is called elastic potential energy. It is given by the formula as follows :

So, 250 J of energy is stored in the spring.

answer: 2×10^-2kg

explanation: density= mass per volume

vol=mass/density

converting to s.i units we have;

3÷1000kg = 0.003

1.5÷100m = 0.15

0.003/0.15 = 0.02kg