A 3.0 kg box is at rest on a table. The static friction coefficient us between the box and table is 0.40, and the kinetic friction coefficient per is 0.10. Then, a 10 N horizontal force is applied to the box.

While the box is at rest, the net vertical force acting on it is

∑ F = n - w = 0

where n = magnitude of the normal force (table pushing up on the box) and w = weight of the box. So we have

n = w = mg = (3.0 kg) (9.8 m/s²) = 29.4 N

The coefficient of static friction between the table and box is 0.40, so the maximum magnitude of static friction is

f = 0.40 n = 0.40 (29.4 N) = 11.76 N

which is to say, the box will not move unless a force larger than this is applied to the box.

10 N is of course smaller than 11.76 N, so the box would stay at rest, and its acceleration would remain 0 m/s².

d

explanation:

v=uf/(u-f)

= 5.10/(5-10) convex lens has positive focal length

=50/-5

=-10 cm (formed at other side)

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees.