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29.436 J/g.°C

Explanation:

We are given;

Mass of tungsten; m_t = 215 g

Initial temperature of tungsten; T_ti = 100°C

Final temperature; T_f = 21.5°C

Mass of water; m_w = 450 g

Initial temperature of water; T_tw = 20°C

From tables, specific heat capacity of water; c_w = 4.184 J/g.C

Thus;

Energy lost by tungsten = energy gained by water

Thus;

215 × c_t × (100 - 21.5) = 450 × 4 184 × (21.5 - 20)

Where c_t is specific heat capacity of tungsten

16877.5c_t = 496800

c_t = 496800/16877.5

c_t = 29.436 J/g.C

ill do it for 100, also this isnt 80 its 40

the results is a decrease in air temperature with an increase of altitude.

explanation: