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The radius of its orbit is .

Explanation:

Let suppose that Callisto rotates around Jupiter in a circular path and at constant speed, then we understand that net acceleration of this satellite is equal to the centripetal acceleration due to gravity of Jupiter. That is:

(1)

Where:

- Angular speed, measured in radians per second.

- Radius of the orbit, measured in meters.

- Net acceleration, measured in meters per square second.

In addition, angular speed can be described in terms of period (), measured in seconds:

(2)

And the net acceleration by the Newton's Law of Gravitation:

(3)

Where:

- Gravitation constant, measured in cubic meters per kilogram-square second.

- Mass of Jupiter, measured in kilograms.

Now we apply (2) and (3) in (1) to derive an expression for the radius of the orbit:

(4)

If we know that , and , then the radius of the orbit of Callisto is:

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