A0.25 kg baseball is in contact with a bat for 0.0075 s and exerts a force of 18,500 n. what impulse is delivered to the ball?

The answer is 138.75 kgm/s

Impulse (I) is the multiplication of force (F) and time interval (Δt): I = F · Δt
It is given:
m = 0.25
F = 18,500 N = 18,500 kgm/s²
Δt = 0.0075 s
I = ?

I = F · Δt = 18,500 5kgm/s² * 0.0075 s = 18,500 * 0.0075 kgm/s² * s = 138.75 kgm/s

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