A spring has an elastic constant of 8.75 x 103 N/m. What is the magnitude of the force required to stretch this spring a distance of 28.6 cm from its equilibrium position?

Given :

A spring has an elastic constant of 8.75 x 10³ N/m.

To Find :

The magnitude of the force required to stretch this spring a distance of 28.6 cm from its equilibrium position.

Solution :

We know, force required to stretch a spring of spring constant k and distance x is given by :

Putting all given values, we get :

Hence, this is the required solution.

i don't understand. explain it clearly

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.