A 235 kg crate is pulled across a horizontal surface with a force of 760 N applied at an angle of 30° above the horizontal. Determine the horizontal component of the applied

force

658.16N

Explanation:

Step one:

given data

mass m= 235kg

Force F= 760N

angle= 30 degrees

Required

The horizontal component of the force

Step two:

The horizontal component of the force

Fh= 760cos∅

Fh=760cos30

Fh=760*0.8660

Fh=658.16N

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