1. Calculate the heat capacity of a piece of wood if 1500.0 g of the wood absorbs 6.750.000 joules of heat, and its temperature changes from 32°C to 57°C.

1.8 J/gºC

Explanation:

From the question given above, the following data were obtained:

Mass (M) = 1500 g

Heat (Q) absorbed = 67500 J

Initial temperature (T₁) = 32 °C

Final temperature (T₂) = 57 °C

Specific heat capacity (C) =?

Next, we shall determine the change in temperature of the wood. This can be obtained as follow:

Initial temperature (T₁) = 32 °C

Final temperature (T₂) = 57 °C

Change in temperature (ΔT) =.?

ΔT = T₂ – T₁

ΔT = 57 – 32

ΔT = 25 °C

Finally, we shall determine the heat capacity of the wood. This can be obtained as follow:

Mass (M) = 1500 g

Heat (Q) absorbed = 67500 J

Change in temperature (ΔT) = 25 °C

Specific heat capacity (C) =?

Q = MCΔT

67500 = 1500 × C × 25

67500 = 37500 × C

Divide both side by 37500

C = 67500 / 37500

C = 1.8 J/gºC

Thus, the heat capacity of the wood is 1.8 J/gºC

inverse v=i*r

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