GIVE ME THIS PRONTO please! its the day befor the samester ends!!!

In Hooke's law, Fspring=kΔx, what does the k stand for?

the amount of force acting on the spring

the constant of gravity

the elastic constant, a number that tells the relative strength of the spring

the distance the spring stretches

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j