A proton accelerates from rest in a uniform electric field of 630 N/C. At one later moment, its speed is 1.50 Mm/s (nonrelativistic because v is much less than the speed of light). (a) Find the acceleration of the proton.

the acceleration of the proton is 6.025 x 10¹⁰ m/s².

Explanation:

Given;

magnitude of electric field, E = 630 N/C

final speed of the proton, v = 1.5 M m/s = 1.5 x 10⁶ m/s

charge of proton, Q = 1.6 x 10⁻¹⁹ C

mass of proton, m = 1.673 x 10⁻²⁷ kg

The force experienced by the proton is calculated as;

Therefore, the acceleration of the proton is 6.025 x 10¹⁰ m/s².

50 inches should be the resultant vector

there are no correct statementd on the list of choices you provided.