1. Deshaun Watson (100 kg) accelerates from rest to 9.0 m/s in 1.5 s. What is the average power output of Deshaun in kW? (2 mark)

P = 5400[W]

Explanation:

We must use the following equation of kinematics to calculate the acceleration.

where:

Vf = final velocity = 9 [m/s]

Vo = initial velocity = 0 (starting from rest)

a = acceleration [m/s²]

t = time = 1.5 [s]

Now with this second equation of kinematics, we can determine the distance traveled.

where:

x= distance [m]

Now we must use Newton's second law which tells us that the sum of forces is equal to the product of mass by acceleration.

∑F = m*a

Now replacing:

Ahora la potencia se puede calcular por medio del producto de la fuerza por velocidad.

where:

P = power [W]

F = force = 600 [N]

v = velocity = 9 [m/s]

one person pulls 90n one way and the other has 100n pulling the other way.

so the net force = 90 - 100 = -10n,

or the ans can be 10n if the picture shows -90n and 100n instead.

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