A race car is accelerating at 5m/s and then speeds up to a final velocity of 12 m/s if the race car driver finished this let of the race in 6 seconds what was the car's acceleration

1.167 m/s^2

Explanation:

Given that a race car is accelerating at 5m/s and then speeds up to a final velocity of 12 m/s if the race car driver finished this let of the race in 6 seconds what was the car's acceleration ?

From the question, the following parameters are given

Initial velocity U = 5 m/s

Final velocity V = 12 m/s

Time t = 6 s

According to the definition of acceleration:

Acceleration = change in velocity per time taken.

I.e

Acceleration =( V - U)/ t

Acceleration =( 12 - 5 )/6

Acceleration = 7/6

Acceleration = 1.167 m/s^2

Therefore, acceleration is 1.167 m/s^2

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz