6. The figure shows a student pushing a 1.22 kg box across a frictionless floor a distance of 5.0 m by applying a force of 30.0 N.
What is the work done on the box by the two forces, Fn and Fa , as it
is pushed 5.0 m along the floor?
F = 12.0 N
F=30.0 N
5 m
A. Work by Fn = 0 Joules Work by Fa = 0 Joules
B. Work by Fn = 0 Joules Work by Fa = 150 Joules
C. Work by Fn = 60 Joules Work by Fa = 0 Joules
D. Work by Fn = 60 Joules Work by Fa = 150 Joules

Abaseball has a mass of 0.145 kg and approaches a bat at 40.0 m/s. after it is hit, the ball leaves the bat at 50.0 m/s directly back. find the impulse of the bat on the ball. 7.25 kg*m/s 13.1 kg*m/s 5.80 kg*m/s 1.45 kg*m/s

In a wind tunnel the speed changes as the cross sectional area of the tunnel changes. if the speed in a 6' x 6' square test section is 100 mph, what was the speed upstream of the test section where the tunnel measured 20' x 20'? use conservation of mass and assume incompressible flow. conservation of mass requires that as the flow moves through a path or a duct the product of the density, velocity and cross sectional area must remain constant; i.e., that ova-constant. a model is being tested in a wind tunnel at a speed of 100 mph if the flow in the test section is at sea level standard conditions, what is the pressure at the model's stagnation point? (a) the tunnel speed is being measured by a pitot-static tube connected to a u- tube manometer. what is the reading on that manometer in inches of water? (b) at one point on the model a pressure of 2058 psf is measured. what is the local airspeed at that point?

How is acceleration calculated? a. initial velocity - final velocity / timeb. initial velocity + final velocity / timec. final velocity - initial velocity / timed. final velocity / timele select the best answer from the choices provided0oood00save and exitnextmark this and return