You took a running leap off a high diving platform. you were running at 2.8m/s and hit the water 2.6 seconds later. how high was the platform, and how far from the edge of the platform did you hit the water? assume your initial velocity is horizontal. ignore air resistance.

Thank you for posting your question here at . Below is the solution:

 Initial values: 

vox = 2.9 m/s (assume that you begin horizontally) 
voy = 0 m/s 
ax = 0 m/s^2 
ay = -9.8 m/s^2 
t = 2.6 s 
xo = 0 
y = 0 

First of all, we are finding yo, or the height. We can use the following kinematics equation: y = yo + voy*t + .5*ay*t^2 

Solve for yo, cancel 0 values: -yo = .5*ay*t^2 

Plug in values: -yo = .5 * -9.8 * 2.6^2 

yo = height = 33.124 meters 

After that, we are to find the horizontal range, or x. We can use the following kinematics equation: x = xo + vox*t + .5*ax*t^2 

Cancel 0 values: x = vox*t 

Plug in values: x = 2.9 * 2.6 

x = horizontal range = 7.54 meters

Answerthe energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.explanationwe define electric potential as the ratio electric potential energy to the charge,    then the following gives us the potential difference,      the formula  may be on your formula sheet.the change in electric potential energy would be the energy that would needed to move it from point a to point b. solving for that, we get    using q = 8.00  × 10⁻¹⁹ c and  δv = 2.00 v, we get    the energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.