A bat, flying at 5.00 m/s, emits a chirp at 40.0 kHz. If this sound pulse is reflected by a wall, what is the frequency of the echo received by the bat

The frequency of the echo received by the bat is 38.8 kHz.

The given parameters:

The observed frequency or frequency received by the bat is calculated by applying Doppler effect as follows;

Since the bat is flying away from the wall the frequency received will be smaller than the actual frequency;

Thus, the frequency of the echo received by the bat is 38.8 kHz.

Learn more about Doppler effect here: link

The answer is below

Explanation:

Firstly, the frequency is received by the wall and then it is reflected and received by the bat.

The frequency received by the wall (f') is given by:

f' =

The - sign is used when the  observer is moving away from the source and + sign when the observer is moving towards the source.

Since the bat is moving towards the wall, we use a positive sign. Hence:

f' =

The frequency reflected and received by the bat f" is:

f'' =

- sign is used when the source moves toward the observer and + is used when the source moves away

since the bat moves towards the wall, then::

f'' =

v = speed of sound in air = 331 m/s, vo = velocity of observer = 5 m/s, vs = velocity of source = 5 m/s. Therefore:

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